Solving Double Integrals: Finding J in R2

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squenshl
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How do I find
J := [tex]\int\int_U y cos(x + y) dA[/tex]
where U = {(x,y) [tex]\in[/tex] R2 : 0 [tex]\leq[/tex] x [tex]\leq[/tex] 2, 1-x [tex]\leq[/tex] x [tex]\leq[/tex] -2 + 2x}.

I drew the picture & i get 2 triangles but not sure what to do with them. Help please.
 
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in rectangular coordinates, dA=dx dy, so the region U describes will give you the limits for the integral.
 
I think you should only be getting one triangle. Try checking your picture against one generated by a graphing tool.

Cheers,
W. =)
 
Very true. I got a triangle & J = -0.5717341110 using maple.