Solving Einstein Equation Confusion: My Notes vs Freidmann Equations

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SUMMARY

The discussion centers on the confusion surrounding the Einstein equation as presented in course notes, specifically the equation G_{ab} - \Lambda g_{ab} = x T_{ab} where x = \frac{8 \pi G}{c^4}. Participants highlight inconsistencies when deriving the Friedmann equations, noting that a negative cosmological constant (-Λ) leads to contradictions in the trace calculations. The consensus suggests that the equation should read G_{ab} + \Lambda g_{ab} = \frac{8 \pi G}{c^4} T_{ab}, indicating a likely typographical error in the original notes. Participants recommend consulting with instructors for clarification.

PREREQUISITES
  • Understanding of General Relativity concepts, particularly the Einstein field equations.
  • Familiarity with the Friedmann equations in cosmology.
  • Knowledge of tensor notation and the significance of the Ricci scalar (R).
  • Basic grasp of cosmological constants and their role in the universe's expansion.
NEXT STEPS
  • Review the derivation of the Friedmann equations from the Einstein field equations.
  • Study the implications of the cosmological constant (Λ) in modern cosmology.
  • Learn about tensor calculus and its application in General Relativity.
  • Consult authoritative texts on General Relativity to clarify common misconceptions.
USEFUL FOR

Students of physics, particularly those studying General Relativity and cosmology, as well as educators seeking to clarify common confusions regarding the Einstein equations and Friedmann models.

latentcorpse
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My notes for a particular course say that [itex]G_{ab} - \Lambda g_{ab}= x T_{ab}[/itex] where [itex]x=\frac{8 \pi G}{c^4}[/itex]
Then they say that the trace of this is [itex]-R+4 \Lambda=xT[/itex]
What?
Surely that's only possible if we have [itex]+\Lambda g_{ab}[/itex] as I have seen in every other text I've ever read?

However, when we derive the Freidmann equations from this we get a [itex]( \frac{\dot{a}}{a})^2=\frac{8 \pi G}{3} \rho -\frac{k}{a^2}+\frac{\Lambda}{3}[/itex]
So if we had [itex]-\Lambda[/itex] on the LHS as suggested in the notes then this will come over to the RHS and give a + as required by the Freidmann equations but now it is all inconsistent with the trace.

This is so confusing! Can anyone clear this up? Thanks.
 
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Are you sure it isn't

[tex]G_{ab} + \Lambda g_{ab}= \frac{8 \pi G}{c^4}<br /> T_{ab}[/tex]

in the original Equation, that is, +Λ instead of -Λ on the left-hand side?

In case your textbook/notes actually state -Λ, then there's a strong possibility of it being a typo, and in this case, just ignore it.

I'd also recommend you to notify your tutor/professor on this.
 

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