Solving Equations for t': Negative Time Confusion

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Pochen Liu
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Homework Statement
How can the answer be negative time?
Relevant Equations
*attached
Equations:
243341


Question:
243342


Using the equation for t' I got the answer -0.00000499756s (Wrong anyway)
As we know the values:
v = 0.67c m/s
x = 3900 m
t = 0.000005 s

Also how can time be negative? Does this mean that event 2 happened before the first event when t = 0?
 
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Pochen Liu said:
Problem Statement: How can the answer be negative time?
Relevant Equations: *attached

Equations:
View attachment 243341

Question:
View attachment 243342

Using the equation for t' I got the answer -0.00000499756s
As we know the values:
v = 0.67c m/s
x = 3900 m
t = 0.000005 s

How can time be negative? Does this mean that event 2 happened before the first event when t = 0?

If events in one reference frame are spacelike separated (i.e. the distance between them is greater than the time between them multiplied by ##c##), then in another frame they may happen in a different order.
 
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PeroK said:
If events in one reference frame are spacelike (i.e. the distance between them is greater than the time between them multiplied by ##c##), then in another frame they may happen in a different order.
What am I doing wrong?
t' = (0.000005 - (0.67*3900)/c)/sqrt(1-0.67^2)
t' = -0.00000499756s

A hint would be amazing! Have I fundementally misinterpreted the equation
 
Pochen Liu said:
What am I doing wrong?
t' = (0.000005 - (0.67*3900)/c)/sqrt(1-0.67^2)
t' = -0.00000499756s

A hint would be amazing! Have I fundementally misinterpreted the equation
I haven't checked the numbers but that looks correct.
 
PeroK said:
I haven't checked the numbers but that looks correct.
Sorry I forgot to mention it's wrong
 
They don't provide us answers sadly