Modular Arithmetic: Solving Equations with 22x^2 = 11 mod 13

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Homework Help Overview

The discussion revolves around solving the equation 22x² ≡ 11 (mod 13) within the context of modular arithmetic. Participants explore various methods to approach the problem while considering the implications of modular constraints.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster considers evaluating the equation by substituting values for x from 0 to 11 and questions if there is a more efficient method. Another participant suggests defining z = x² to simplify the equation into a more manageable form. There is also a discussion about the potential for proving the absence of solutions without exhaustive trial and error.

Discussion Status

The conversation is ongoing, with participants sharing different perspectives on solving the equation. Some guidance has been offered regarding methods to approach the problem, but there is no explicit consensus on a single solution path.

Contextual Notes

Participants note that the modular arithmetic context (mod 13) makes trial and error feasible, but they also acknowledge the challenges posed by larger moduli, which could complicate the problem significantly.

rashida564
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Homework Statement
22x^2 + 13(x + 2y)^3 = 11 has no integer solutions x and y
Relevant Equations
Module asthmatic.
I am thinking of taking modular of 13 to both sides of equation. So it will become
22x^2 is 11 mod 13.
And try all the values from x equal to zero to x equal to 11.
Is their easier way to solve it
 
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I think it is a good idea, what I would do is to define ##z=x^2## to have the equation ##az=c \pmod{m}## which is very easy to solve without trying an error (which is not a problem for this small numbers, but its always nice to have a method to solve things), and then you only need to solve ##z = x^2 \pmod{m}## which again can be done without trying an error.
 
How can I find that there's no solution using your method, there's no integer solution
 
Well, as I said, the equations ##ax=b \pmod{m}## and ##x^2=a \pmod{m}## are very common and important and you can find the solutions of both without trying and error (if you have not studied this then it's OK). Of course, that means that, if they don't have a solution you can prove it without having to try all the possibilities. (As I said, since you are working ##\pmod{13}## try and error is not a big deal, but if you were working at ##mod{97}## it would be really long, and a number with 10 digits would be impossible except maybe for a computer.)
 
"Modular asthmatic"? Doesn't modular arithmetic have enough problems without being asthmatic as well?
 

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