Solving Equilibrium Expression: Balancing HOCl Reaction for Basic Solution

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SUMMARY

The discussion focuses on balancing the equilibrium expression for the reaction of hypochlorous acid (HOCl) in a basic solution. The balanced reaction derived is 2ClO- <--> Cl- + ClO2-. This transformation occurs because in a basic environment, weak acids like HOCl dissociate to form their conjugate bases, which in this case is ClO-. The equilibrium constant expression provided is K = [Cl-][ClO2-][H+]^2/[HOCl]^2, which is crucial for understanding the dynamics of the reaction.

PREREQUISITES
  • Understanding of acid-base chemistry, specifically weak acids and their conjugate bases.
  • Familiarity with equilibrium expressions and how to manipulate them.
  • Knowledge of the concept of dissociation in basic solutions.
  • Basic proficiency in chemical reaction balancing techniques.
NEXT STEPS
  • Study the dissociation of weak acids in basic solutions, focusing on examples like acetic acid.
  • Learn about equilibrium constants and how to calculate them for various reactions.
  • Explore the concept of conjugate acid-base pairs in detail.
  • Review balancing chemical equations, particularly for reactions involving acids and bases.
USEFUL FOR

Chemistry students, educators, and anyone involved in chemical equilibrium studies will benefit from this discussion, particularly those focusing on acid-base reactions and equilibrium expressions.

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Homework Statement



Aqueous solutions of hypochlorous acid, HOCl, can be unstable due to the reaction:

2HOCl <--> Cl- + ClO2- + 2H+

(c) Write out the balanced reaction appropriate to basic solution corresponding to the reaction given above.

Homework Equations



K = [Cl-][ClO2-][H+]^2/[HOCl]^2

The Attempt at a Solution



This question is part of a bigger equilibrium constant experssions' problem. I have answered all the parts to this question, I just don't understand what they are asking for here in part (c)?

The answer given is:

2ClO- <--> Cl- + ClO2-

I don't understand how they got to that?
 
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Think: what happens to the weak acid in a basic solution?

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