Solving Fluid Questions: 2 Spheres & U-Tube | 65 Characters

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In summary, the first conversation discusses the determination of acceleration for a thin spherical shell filled with helium and released in a pool of water, while the second conversation involves finding the height of oil in a U-tube containing water and oil. Both questions require the use of formulas and understanding of weight and density. For the first question, a freebody diagram can be used to find the net force on the sphere, while for the second question, the weight of the oil is equal to the weight of the water it displaces and their respective densities must be considered.
  • #1


1. A thin spherical shell with a mass of 3.82 kg and a diameter of 0.200 m is filled with helium (density = 0.180 kg/m3). It is then released from rest on the bottom of a pool of water that is 3.73 m deep. Neglecting frictional effects, determine the value of that acceleration.

Can anyone help me with this question? I found the volume of the sphere v = m/density, and the area of the sphere, but got stuck on how to actually find the acceleration, would you have to use Force=Pressure/Area somewhere?

2. A U-tube of circular diameter 5.60 mm initally contain just water. If 4.00 milliliters(cm^3) of oil is added to the left hand side of the tube the level of the oil is 6.8 mm higher than the level of the water in the right hand side of the tube. Determine the height of the oil.

Im confused on what they mean by the circular diameter and do you need that to solve the question. I tried using the formula for volume of a cylinder, solving for height, but I don't think that helped at all. Can anyone give me some pointers?

Theres no examples like this in my notes, or in my text, and the assingment is due in 2 hours. Thanks
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  • #2
For the first question you should draw a freebody diagram and from there you can get the net force acting on the sphere: buoyant force - weight.

For the second question I think the circular diameter is best described by a donut, from the inside to the outside is 5.6 mm. The total weight of the oil is equal to the weight of the water it displaces, so
h(weight of oil)=(h-6.8)(weight of water). g is the same for both so basically you just have to use their respective densities.

Hope that helps a little.

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