Solving for "a" in Square Root Equation

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Asla
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Homework Statement


Get the value of a if
[itex]\sqrt{6-\sqrt{a}}[/itex]+[itex]\sqrt{6+\sqrt{a}}[/itex]=[itex]\sqrt{14}[/itex]


The Attempt at a Solution


nothing succesfull
Feel free to move this thread,..I actually place it here to tap more brains
 
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tiny-tim said:
square? :wink:
What do you mean?I square both sides?
 
tiny-tim said:
square as many sides as you can find! :biggrin:
It gives me this:
12+[itex]\sqrt{36-a}[/itex]=14
could I be going wrong somewhere?
 
Damn it I had never felt so foolish,..thanks I got it
 
Asla said:
It gives me this:
12+[itex]\sqrt{36-a}[/itex]=14
could I be going wrong somewhere?

(a+b)² = a² + 2ab + b²

Nevermind. You've already gotten it!