Integration question involving square root

There are several different ones you could try, so just pick one and see where it leads you. Good luck!In summary, the conversation is about integrating two equations with a constant k and using a substitution to simplify the integral. The person is unsure of what substitution to use and is seeking help. They are advised to try different things and look for a trig substitution.
  • #1
binbagsss
1,326
12
Member warned that an effort must be shown

Homework Statement



How to integrate

## \frac{dx}{dt}=\sqrt{\frac{k}{x}-1}##

AND

## \frac{dx}{dt}=\sqrt{\frac{k}{x}+1}##

k a constant here.

I'm unsure what substitution to do.
Many thanks in advance.

Homework Equations

The Attempt at a Solution



I can't really get started as I'm unsure what substition is needed.
I think a trig but don't know what?many thanks in advance.
 
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  • #2
binbagsss said:

Homework Statement



How to integrate

## \frac{dx}{dt}=\sqrt{\frac{k}{x}-1}##

AND

## \frac{dx}{dt}=\sqrt{\frac{k}{x}+1}##

k a constant here.

I'm unsure what substitution to do.
Many thanks in advance.

Homework Equations

The Attempt at a Solution



I can't really get started as I'm unsure what substition is needed.
I think a trig but don't know what?many thanks in advance.

You need to show more effort. Just try lots of different things. Some of them will be a wast of time, but others should work. Trying it on your own first is the only way to learn.
 
  • #3
Try expressing your integrals in a form that can be found in a table of integrals. It took me two minutes to find the answer to your question. If you are supposed to derive your answer from first principles, at least you will have something to work towards.
 
  • #4
Fred Wright said:
Try expressing your integrals in a form that can be found in a table of integrals. It took me two minutes to find the answer to your question. If you are supposed to derive your answer from first principles, at least you will have something to work towards.

I've been warned already. cheers for the input though my good pal ;)
 
  • #5
binbagsss said:
I can't really get started
A good start would be to write as an integral, in as simple a form as you can, instead of leaving it as a differential equation.
Next, look for a substitution that gets k out of the way. Then think about a trig substitution.
 

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