Solving for c: Speed of Q2 in Q1 Reference Frame

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SUMMARY

The discussion focuses on the calculation of the speed of Q2 as observed from the reference frame of Q1 using the relativistic velocity addition formula. The correct formula is given by v_{CA} = (v_{BA} + v_{CB}) / (1 + (v_{BA} v_{CB} / c^2)). The user initially miscalculated the speed of Q2, arriving at 0.922c instead of the correct value. The discussion emphasizes the importance of correctly identifying the reference frames and the signs of the velocities involved.

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Pochen Liu
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Homework Statement
Stellar system Q1 moves away from us at a speed of 0.860c. Stellar system Q2, which lies in the same direction in space but is closer to us, is moving away from us at a speed 0.560c. What multiple of c gives the speed of Q2 as measured by an observer in the reference frame of Q1?
Relevant Equations
*attached
I've tried using this equation:

243343

Where:
u' = 0.86c
v = 0.3c
u = Is the speed of Q2 as measured by an observer in the reference frame of Q1 = 0.922c

Where have I gone wrong? Have I missed a negative symbol?
 
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Before plugging the numbers in, make sure you understand the variables in velocity addition formula.

If you have an observer ##A##, a second observer ##B##, and an object ##C##, then let:

  • ##v_{BA}## = the velocity of ##B## as measured by ##A##.
  • ##v_{CB}## = the velocity of ##C## as measured by ##B##.
  • ##v_{CA}## = the velocity of ##C## as measured by ##A##.
If all three velocities are in a straight line, then according to relativity,

##v_{CA} = \dfrac{v_{BA} + v_{CB}}{1+ \frac{v_{BA} v_{CB}}{c^2}}##

In your case, the three objects are:
  1. You = ##A##
  2. Q1 = ##B##
  3. Q2 = ##C##

In this case, what they are asking is not ##v_{AC}##. They tell you that that is equal to ##0.860c##. They are asking for ##v_{BC}##.

So you have two options, that work the same:
  • Write down the formula for ##v_{CA}, v_{BA}, v_{CB}## and solve, algebraically for ##v_{CB}## in terms of the other two, or
  • Switch the labels around. Let ##A## be Q1, ##B## be you, and ##C## be Q2.
If you do the second one, you have to remember that if Q1 is moving at 0.860c relative to you, then you are moving at -0.850c relative to Q1.
 
Pochen Liu said:
Problem Statement: Stellar system Q1 moves away from us at a speed of 0.860c. Stellar system Q2, which lies in the same direction in space but is closer to us, is moving away from us at a speed 0.560c. What multiple of c gives the speed of Q2 as measured by an observer in the reference frame of Q1?
Relevant Equations: *attached

I've tried using this equation:

View attachment 243343
Where:
u' = 0.86c
v = 0.3c
u = Is the speed of Q2 as measured by an observer in the reference frame of Q1 = 0.922c

Where have I gone wrong? Have I missed a negative symbol?
Try the calculation using the classical velocity addition and see what you get.
 
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