Solving for Electric Force: Two Point Charges

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Homework Help Overview

The problem involves two point charges, 3q and q, positioned along the x-axis, with the goal of finding the point between them where the net force on charge q is zero. The context is centered around electric forces and fields in electrostatics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss whether the problem refers to net electric field or net electric force, with some suggesting that the net electric field is the focus due to the presence of two charges. There are attempts to clarify the implications of charge repulsion and the conditions under which the net force could be zero.

Discussion Status

Some participants have provided mathematical reasoning and attempted to derive a solution, while others express confusion about the concepts involved. There is a mix of interpretations regarding the problem's wording and the underlying physics principles.

Contextual Notes

Participants note the potential for misunderstanding due to the phrasing of the problem and the influence of teaching styles on comprehension. There is also mention of varying levels of comfort with the material among participants.

netteo
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Homework Statement



Two point charges, 3q and q lie along x-axes. 3q is at 0.00 m and q is at 3.0m.
Find the point between the 2 charges at which the net force on charge q is zero.

Homework Equations



F=kq1q2/r^2

The Attempt at a Solution


Really can't figure this one out. Missed the first lesson.
 
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are they talking about net electric field or net electric force?
 
I'm pretty sure they mean net electric field, since there are only 2 charges. Otherwise, the electric force would be the same so long as the two charges are in the same place and if a point charge is placed somewhere between. I mean, in that case, the net force on the point charge anywhere between the two charges would be zero, but that the charge on q would be the same.
 
The answer is 1.9m.

I still don't understand it because since both the charges are positive, wouldn't the forces be in the other direction (no forces in between both the charges) since they are going to repel each other?
 
If they are talking about the net electric field being that of zero, then here's what you do:

make K(3q)/((3-r)^2)=k(q)/((r)^2)

Therefore,

3r^2=(3-r)^2
and

0=9 -6r -3r^2 +r^2

use quadratic formula to solve

6 +/- sqrt(36 + 4(2)(9))/2(-2)=r

(6+/- 10.39)/-4=1.1meters
and 3-1.1=1.9 AH! :D there's your answer!
 
Oh wow.. thanks!
That makes so much more sense than what my TA taught me!

Totally made my day! Thank you so much! :D
 
I'm also in physics 2 and I had a bit of trouble understanding why this is true. I mean, it has everything to do with distance and electric field.
 
I guess my lecturer just worded it weirdly.. =/
 
My professor is funny guy, but he and I talk a lot. So, It's cool. The best thing to do is if you get a better professor that fits your style of learning. I'm the kind of person who learns if he feels free in the classroom. So, if a professor is extremely strict and too authoritarian, I'd hate the professor.
 

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