Solving for Height of Falling Flowerpot

In summary, the flowerpot fell from a height of 3.27 meters in 1/4 of a second. The equations used to calculate its velocity and height were v = d/t and h = (v^2 - v0^2) / 2g, respectively. However, the initial velocity of the pot was 0 and the correct equation for height is h = 1/2*g*t^2. The bottom of the window is at a height of 1.23 meters.
  • #1
mmoadi
157
0

Homework Statement



A flowerpot falls past two meter tall window in ¼ of a second. From what height did the flowerpot fall?

Homework Equations



To calculate the velocity of the pot while this is passing the window: v = d/t
To calculate the height: v^2= v0^2 = 2gh → h= (v^2 - v0^2) / 2g

The Attempt at a Solution



v = d/t = 2m / (1/4s) = 8 m/s

Since the initial velocity is 0, do we plug the 8m/s in place of the v squared, so the equation would be h= (8 m/s)^2 - 0 / 2 * 9.8 m/s^2 and the final answer should be 3.27m, right??
 
Physics news on Phys.org
  • #2
While crossing the window, the flower pot is not moving with constant velocity. So your calculation of velocity is wrong.
Initial velocity of the flower pot vo = 0.
If the top edge of the window is at a height h, then
h = 1/2*g*t^2.
The bottom of the window is at a height h' =...?
Now h' = 1/2*g*(...)^2 ?
 
  • #3


Yes, that is correct. The final answer should be approximately 3.27m. Good job using the appropriate equations to solve for the height of the falling flowerpot.
 

Related to Solving for Height of Falling Flowerpot

What is the equation for solving the height of a falling flowerpot?

The equation for solving the height of a falling flowerpot is h = 1/2 * g * t^2, where h is the height, g is the gravitational constant (9.8 m/s^2), and t is the time in seconds.

What is the value of the gravitational constant?

The gravitational constant, denoted as g, is a physical constant with a value of approximately 9.8 m/s^2. This value is the same for all objects on Earth, regardless of their mass.

How do you measure the time in seconds for the equation?

The time in seconds can be measured using a stopwatch or a timer. Begin the timer when the flowerpot is dropped and stop it when it hits the ground. The resulting time will be used in the equation.

Can this equation be used for any falling object?

Yes, this equation can be used to solve for the height of any falling object, as long as the acceleration due to gravity remains constant (9.8 m/s^2). This includes objects of different masses and shapes.

What are some factors that may affect the accuracy of the calculated height?

Some factors that may affect the accuracy of the calculated height include air resistance, wind, and the shape and weight distribution of the flowerpot. These factors may cause the flowerpot to deviate from a purely vertical path, affecting the time and height measured.

Similar threads

  • Introductory Physics Homework Help
Replies
8
Views
5K
  • Introductory Physics Homework Help
Replies
25
Views
601
  • Introductory Physics Homework Help
Replies
3
Views
449
Replies
5
Views
476
  • Introductory Physics Homework Help
2
Replies
38
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
358
  • Introductory Physics Homework Help
Replies
3
Views
358
  • Introductory Physics Homework Help
Replies
11
Views
971
Back
Top