Solving for q2: Find Charge of Particle 2

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Homework Help Overview

The problem involves two charged particles in a vacuum, where one charge (q1) is given as +3.5 µC, and the task is to determine the charge of the second particle (q2) based on the attractive force experienced by the first particle. The distance between the charges is specified as 0.25 m, and the force is noted to be 2.3 N.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Coulomb's law to find q2, questioning the correctness of their equations and the implications of the attractive force on the signs of the charges. There is also a consideration of whether like charges attract or repel.

Discussion Status

Participants are actively engaging with the problem, attempting to clarify their understanding of the forces involved and the correct application of formulas. Some guidance has been offered regarding the need to solve for q2 algebraically before substituting values, and there is an acknowledgment of the importance of determining the sign of the charge.

Contextual Notes

There is a mention of a potential mistake regarding the value of the first charge, and participants are navigating the implications of attractive versus repulsive forces in the context of their calculations.

rcmango
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Homework Statement



In a vacuum, two particles have charges of q1 and q2, where q1 = +3.5 µC. They are separated by a distance of 0.25 m, and particle 1 experiences an attractive force of 2.3 N. What is q2 (magnitude and sign)?

Homework Equations





The Attempt at a Solution



not sure why this wouldn't work 2.3 N = (8.99 x 10^9 * Q2)/ .25^2

should that work? and would the sign be + or -?

thanks.
 
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rcmango said:

Homework Statement



In a vacuum, two particles have charges of q1 and q2, where q1 = +3.5 µC. They are separated by a distance of 0.25 m, and particle 1 experiences an attractive force of 2.3 N. What is q2 (magnitude and sign)?

Homework Equations





The Attempt at a Solution



not sure why this wouldn't work 2.3 N = (8.99 x 10^9 * Q2)/ .25^2

should that work? and would the sign be + or -?

thanks.

you want the force to be attractive, as stated in the problem. do like charges attract or repel?
 
like charges repel. however, is my formula equation correct?
 
You are missing a charge, remember

[tex]F = k \frac{qQ}{r^2}[/tex]
 
Okay, I see, so then I solve for Q2, correct?

which shows now 2.3 N = ((8.99 x 10^9) * (2.3) * (Q2) )/ .25^2

i get something like: -4.57 x 10^-12 C
 
You should solve for what you want algebraically before you put in numbers. It is a lot easier that way. So you are right, you want the value of the other charge.

[tex]q_2 = \frac{r^2 F}{kq_1}[/tex]

in terms of the numbers that would be... (you do it)

*note: you made a mistake for the value of the first charge. Also note that I just gave you the magnitude of the charge, you will have to figure out the sign.
 

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