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- Homework Statement
- A bug crawls outward from the center of a CD spinning at 200 revolutions per minute. coefficient of static friction between bug's sticky feet and disc surface is 1.2. How far does the bug get from the center before slipping?

- Relevant Equations
- centripetal acceleration = (v^2 / r) = (4pi^2r)/ t^2

F_net= ma (newton's second law)

static friction = "mu" F_n (normal force)

200rpm/60 = 3.33 revolutions per second

I set (μ_s) *mg equal to (m*4pi^2r)/T^2

Then I solved for r

However, when I solve for r, I get 3.24 meters which seems much too far for a bug to travel. Should I have divided by something somewhere instead of multiplied?

Then I solved for r

However, when I solve for r, I get 3.24 meters which seems much too far for a bug to travel. Should I have divided by something somewhere instead of multiplied?