Solving for the speed of a recoiling H atom

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Homework Help Overview

The problem involves a hydrogen atom transitioning from an excited state (n=2) to the ground state (n=1) by emitting a photon, and the goal is to determine the speed of the recoiling atom after the emission. The context is within quantum mechanics and energy transitions.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the energy difference between the two states using the formula E = -13.6/n^2 and relates it to the kinetic energy of the recoiling atom. Some participants suggest using conservation of momentum as an alternative approach.

Discussion Status

The discussion has seen various approaches, with one participant indicating that using conservation of momentum resolved their issue. However, there is no explicit consensus on the best method to solve the problem, and multiple interpretations are being explored.

Contextual Notes

The original poster mentions not arriving at the correct answer using their method, indicating potential gaps in understanding or application of the concepts involved.

silex
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Hey everyone,
I have a practice problem that I can't figure out:

A hydrogen atom is initially at rest and in the n=2 state. Subsequently, it decays to the ground state by emitting a photon. What is the speed of the recoiling atom afterwards? (Mass of H atom = 1.67 * 10^-27 kg)

My approach is to find the difference in energy between the two states by using E = -13.6/n^2 for each state (n=1 and n=2), then finding the energy difference, and setting that equal to (1/2)mv^2 and solving for v, but I'm not getting the right answer. (The correct answer is 3.4 m/s)
Can someone help me with this?

Thanks in advance

-s
 
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use 4 in work reverse?
 
I would use conservation of momentum.
 
Using conservation of momentum solved the problem, thanks.
 

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