Why Is the Calculated Wavelength Incorrect in This Hydrogen Atom Problem?

The deBroglie wavelength is given by λ = h/p, where p is the momentum of the electron. In summary, when trying to calculate the energy of an electron in the first excited state of a hydrogen atom, it is important to use the correct formula and to clarify what is being asked for, as confusion can arise when using the incorrect units. In this case, the correct formula for finding the wavelength of the photon emitted in the transition from the first excited state to the ground state is λ = hc/E, where E is the energy difference between the two states.
  • #1
Suyash Singh

Homework Statement


Calculate energy of electron in first excited state of hydrogen atom.

Homework Equations


n=2
when i use E=-13.6 (z/n)^2
and then use E=hc/lamda(wavelength)
then wavelength is coming wrong

The Attempt at a Solution


the correct answer is 6.68 armstrong.
 
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  • #2
Ångström (not armstrong) is a unit of length, not a unit of energy. It is likely that you are not being asked what you have stated that you are being asked about here. The question is likely what the wavelength of the photon emitted when the electron in the first excited state of hydrogen transits to the ground state. This is not the same thing as the energy in the first excited state.
 
  • #3
Suyash Singh said:
when i use E=-13.6 (z/n)^2
and then use E=hc/lamda(wavelength)
then wavelength is coming wrong
Are you trying to find the deBroglie wavelength of the electron when it is in the first excited state? If so, the formula E = hc/λ is not the correct formula.
 

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