Solving for X: 0.012M/(d-x)^2=M/x^2

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Homework Help Overview

The discussion revolves around solving the equation 0.012M/(d-x)^2 = M/x^2, where M represents the mass of the Earth and d is the distance between the Earth and the Moon. Participants are attempting to isolate x in this context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore various algebraic manipulations, including cross-multiplying and rearranging terms. Some suggest dividing by constants to simplify the equation, while others express concerns about losing potential solutions when extracting square roots. Questions arise regarding the meaning of the variable d and its implications in the problem.

Discussion Status

There is an active exploration of different algebraic approaches, with some participants offering alternative methods for isolating x. Concerns about the validity of certain steps, particularly regarding the extraction of square roots, have been raised, indicating a productive dialogue without a clear consensus on the best approach.

Contextual Notes

Participants note the specific values for M and d, which are essential for solving the equation, and there is a discussion about the dimensionality of d in relation to its physical meaning.

thomasrules
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For some reason i can't solve for x:

0.012M/(d-x)^2=M/x^2

I have M value: (5.98)(10)^24

d is: (3.84)(10)^5
 
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i started with cross multiplying:

0.012Mx^2=M(d-x)^2

0.012Mx^2=M(d^2-2dx+x^2)

then i divided both sides by the left side and crossed out M.

From there I don't know what to do
 
After you divided both sides by M and then divided both sides by .012, you should have wound up with:

x^2=\frac{d^2-2dx+x^2}{.012}

Split the right side up into three fractions:

x^2=\frac{d^2}{.012}-\frac{2dx}{.012}+\frac{x^2}{.012}

Substitute in your value for d. That should leave you with something you can work with.
 
Actually, I wouldn't divide both sides by 0.012, just because I don't like fractions!

0.012x2= d2- 2dx+ x2 is the same as (subtract 0.012x2 from both sides)
0.988x2- 2dx+ d2= 0.

With d= 3.85 x 105, d2= 1.48225 x 1011 so your equation is
0.988x2- (7.7 x 105)x+ 1.48225 x 1011= 0.

You can solve that with the quadratic formula.
 
does d in this case stand for difference like in calculus or is it just any other variable?
 
By,the looks of it,it's a dimensionful number...

Daniel.

PS.Got it,it's the mean distance Earth-Moon and M is the Earth's mass... :-p :approve: And it's in Km.
 
couldnt you first divde M on both sides and then find the square root??

as in

\frac{0.012M}{(d-x)^2} = \frac{M}{x^2}
which then gives

\frac{0.012}{(d-x)^2} = \frac{1}{x^2}

and then find the square rooton both sides

\frac{\sqrt{0.012}}{d-x} = \frac{1}{x}

then cross multiply and solve without need for a quadratic??
 
I'm sorry,but it doesn't work that way.You need to consider the modulus when extracting sqrt,which would complicate the problem...

Daniel.
 
  • #10
see i think it's this,
0.012M/(d-x)^2=M/x^2

cross multiply,

x^2/(d-x)^2=M/0.012M

x/(d-x)={1/0.012}^1/2 (that is sq root)

x/(d-x)=9.13

dividing the numerator & denominator by x

1/{(d/x) - 1}=9.13

{(d/x) - 1}=1/9.13
=0.11

(d/x)=1+.11
=1.11

since,d is: (3.84)(10)^5,we have

x=d/1.11
=(3.84)(10)^5/1.11
=345,945.95 units
 
  • #11
jackal said:
see i think it's this,
0.012M/(d-x)^2=M/x^2

cross multiply,

x^2/(d-x)^2=M/0.012M

x/(d-x)={1/0.012}^1/2 (that is sq root)

THAT IS DEVIOUS...U should have a \pm sign...


Daniel.
 
  • #12
if its correct please tell me. :smile:
 
  • #13
I thought i put in a very obvious way... :-p It's wrong.By inappropriately extracting square root,u lost one (possibly viable) solution.

Daniel.
 

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