Solving for x: log 3 (x^2 -5x+6) - log 2 (2-x) = 2

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Homework Help Overview

The problem involves solving the equation log 3 (x^2 - 5x + 6) - log 2 (2 - x) = 2, which includes logarithmic expressions with different bases. The subject area pertains to logarithmic functions and algebraic manipulation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the interpretation of the logarithmic expressions, questioning whether the equation should be viewed as a single logarithm or as separate terms. Some have attempted algebraic manipulation but express uncertainty about how to isolate x.

Discussion Status

The discussion is ongoing, with participants clarifying the problem statement and sharing their attempts at manipulation. There is no explicit consensus on the approach, but some productive lines of reasoning have been explored regarding the structure of the equation.

Contextual Notes

Participants note the complexity introduced by the different logarithmic bases and express concern over the clarity of the problem statement. There is a shared understanding that the equation may require careful handling due to these factors.

JoanF
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Homework Statement



Find x:

log 3 (x^2 -5x+6) - log 2 (2-x) = 2

Homework Equations





The Attempt at a Solution


I tried and got:
(3-x).[(2-x)^1-log 2 (3)] = 9

but I don't know how to get x here ...
 
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JoanF said:

Homework Statement



Find x:

log 3 (x^2 -5x+6) - log 2 (2-x) = 2
Some clarification, please. Is this
log[3(x2 - 5x + 6)] - log[2(2 - x)] = 2

or
log3(x2 - 5x + 6) - log2(2 -x) = 2
?
JoanF said:

Homework Equations





The Attempt at a Solution


I tried and got:
(3-x).[(2-x)^1-log 2 (3)] = 9

but I don't know how to get x here ...
 
Mark44 said:
Some clarification, please. Is this
log[3(x2 - 5x + 6)] - log[2(2 - x)] = 2

or
log3(x2 - 5x + 6) - log2(2 -x) = 2
?

it is log3(x2 - 5x + 6) - log2(2 -x) = 2
 
Are you sure you have the problem written correctly? It's very messy with the two log bases. I got to x2 - 5x + 6 = 9(2 - x)(1/log32)
 
Mark44 said:
Are you sure you have the problem written correctly? It's very messy with the two log bases. I got to x2 - 5x + 6 = 9(2 - x)(1/log32)

You got the same I got


Yes I'm sure ...
 

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