Finding Sup and Inf in Real Analysis: x^2 - 5x + 6 < 0 and x^2 + 1 = 0

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Homework Help Overview

The discussion revolves around finding the supremum and infimum of various sets defined by inequalities and equations in real analysis, specifically focusing on the expressions x^2 - 5x + 6 < 0 and x^2 + 1 = 0.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the infimum and supremum of the set defined by the inequality x^2 - 5x + 6 < 0, with one participant providing values of 2 and 3. There is confusion regarding the interpretation of the second set, { x^2 - 5x + 6 | x ∈ ℝ}, with assumptions made about its range. The third set, {x | x^2 + 1 = 0}, is noted to have no real solutions, leading to a discussion about the existence of infimum and supremum.

Discussion Status

Participants are actively checking each other's reasoning and interpretations regarding the sets. Some guidance has been offered on the interpretation of the second set, and there is acknowledgment of the need for clarification on the third set.

Contextual Notes

There is mention of confusion regarding the notation used in TeX for curly brackets, which may affect the clarity of the expressions presented.

converting1
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find the sup and inf of the following sets:

{ x | x^2 - 5x + 6 &lt; 0 }

I got the inf and sup to be 2 and 3 respectively

{ x^2 - 5x + 6 | x \in ℝ}
here I was rather confused what this is saying. I'm assuming it's taking about the graph x^2 - 5x + 6 and assumed this was between [-1/4, ∞] so inf = -1/4 and sup does not exist as it is not bounded from above.

{x | x^2 + 1 = 0 }
as I'm in a real analysis class, there isn't a real number such that x^2 + 1 = 0, so inf and sup do not exist

could anyone check my answers and if my reasoning is correct, especially for the second one please

I don't understand why the curly brackets are not showing, but there should be curly brackets around all above in tex
 
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converting1 said:
find the sup and inf of the following sets:

\{ x | x^2 - 5x + 6 &lt; 0 \}

I got the inf and sup to be 2 and 3 respectively

Looks good.

{ x^2 - 5x + 6 | x \in ℝ}
here I was rather confused what this is saying. I'm assuming it's taking about the graph x^2 - 5x + 6 and assumed this was between [-1/4, ∞] so inf = -1/4 and sup does not exist as it is not bounded from above.

It's talking about the range, so yes, that looks right too.

{x | x^2 + 1 = 0 }
as I'm in a real analysis class, there isn't a real number such that x^2 + 1 = 0, so inf and sup do not exist

could anyone check my answers and if my reasoning is correct, especially for the second one please

I don't understand why the curly brackets are not showing, but there should be curly brackets around all above in tex

The curly brackets have a special use in TeX, so to display then you use \{ and \} as I did editing your first set.
 
LCKurtz said:
Looks good.



It's talking about the range, so yes, that looks right too.



The curly brackets have a special use in TeX, so to display then you use \{ and \} as I did editing your first set.

thank you for a fast reply,

is the last one correct too as you did not comment on that?
 
converting1 said:
thank you for a fast reply,

is the last one correct too as you did not comment on that?

I would say so as long as your text doesn't have some special convention for empty sets.
 
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