Integrate: (x^2 + 4)/ (x^2+5x-6) dx

In summary, the integrand in this homework problem is a rational function and was integrated to find the sum of partial fractions. A and B were found by comparing coefficients and solving simultaneous equations.
  • #1
beaf123
41
0

Homework Statement



"Express the integrand (what does "integrand" mean?) as a sum of partial fractions and evaluate the integrals.

∫(x + 4)/ (x^2+5x-6) dx

Homework Equations


The Attempt at a Solution



x^2+5x-6 = (x-1)(x+6)

Gives:

∫ A/(x-1) + B/(x+6) dx

Findig A and B:

A(x+6) + B(x-1)

A+B=1

6A-B =4

A= 5/7
B= - (2/7)Then:

∫ (5/7) (1/x-1) dx +∫ - (3/7)(1/x+6) dx

Gives I think:

5/7ln(x-1) -2/7ln(x+6)But its wrong accordng to the solution. I can post the solution here if you want me to:
 
Last edited:
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  • #2
beaf123 said:

Homework Statement



"Express the integrand (what does "integrand" mean?) as a sum of partial fractions and evaluate the integrals.

∫(x + 4)/ (x^2+5x-6) dx

Homework Equations


The Attempt at a Solution



x^2+5x-6 = (x-1)(x+6)

Gives:

∫ A/(x-1) + B/(x+6) dx

Findig A and B:

A(x+6) + B(x-1)

A+B=1

6A-B =4

A= 5/7
B= - (3/7)Then:

∫ (5/7) (1/x-1) dx +∫ - (3/7)(1/x+6) dx

Gives I think:

5/7ln(x-1) -3/7ln(x+6)But its wrong accordng to the solution. I can post the solution here if you want me to:

The integrand is the expression being integrated, in this case, the rational function [tex]\frac{x+4}{x^2+5x-6}[/tex]

How did you get A+B=1 ?
 
  • #3
Okey, thanks.

A(x+6) + B(x-1) = x+4

Ax +Bx +6A -B = x+4

Ax + Bx = xA+B =1
 
  • #4
beaf123 said:
Okey, thanks.

A(x+6) + B(x-1) = x+4

Ax +Bx +6A -B = x+4

Ax + Bx = x


A+B =1

Oh I see, you were comparing coefficients :smile:

Sorry I didn't spot your error before, but you incorrectly solved the simultaneous equations in A and B. 1 - 5/7 = 2/7
 
  • #5
Oh, I changed it now. It is correct so far, but I don't understand how they get 5/7ln(x-1) -2/7ln(x+6) to become ( from solution): (1/7)ln[(x+6)^2(x-1)^5] + C
 
  • #6
beaf123 said:
Oh, I changed it now. It is correct so far, but I don't understand how they get

5/7ln(x-1) -2/7ln(x+6)

to become ( from solution):

(1/7)ln[(x+6)^2(x-1)^5] + C
That should be
5/7ln(x-1) + 2/7ln(x+6)​
Then use properties of logarithms to get the desired result.

Of course the given answer includes the constant of integration.
 

1. What is integration?

Integration is a mathematical process that involves finding the area under a curve on a graph. It is essentially the reverse of differentiation, which involves finding the slope of a curve at a specific point.

2. What is the formula for integration?

The formula for integration is ∫f(x) dx = F(x) + C, where f(x) is the function to be integrated, F(x) is the antiderivative of f(x), and C is the constant of integration.

3. How do you solve an integration problem?

To solve an integration problem, you need to first identify the function to be integrated and then use integration techniques such as substitution, integration by parts, or partial fractions to find the antiderivative. Finally, substitute the limits of integration into the antiderivative to find the definite integral.

4. What is the solution to ∫(x^2 + 4)/ (x^2+5x-6) dx?

The solution to ∫(x^2 + 4)/ (x^2+5x-6) dx is (x+4)ln|x-1| - 3ln|x+6| + C, where C is the constant of integration.

5. Can integration be used in real-world applications?

Yes, integration has many real-world applications, such as calculating the area under a curve to determine displacement, velocity, or acceleration in physics, finding the total cost or profit in economics, and determining the probability of events in statistics.

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