Solving Force and Inertia in Equation of Motion

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SUMMARY

The discussion focuses on the relationship between force, inertia, and angular acceleration in the context of a piston connected to a flywheel. The key equations established are F = ma for linear motion and T = Ia for rotational motion, where T represents torque and I represents moment of inertia. The participant concludes that by calculating the resultant force from the piston and applying it to the flywheel's radius, one can derive the angular acceleration of the flywheel. This demonstrates the direct application of linear equations to rotational dynamics.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Familiarity with rotational dynamics concepts (Torque, Moment of Inertia)
  • Knowledge of angular motion equations (θ, ω, α)
  • Basic principles of mechanics involving pistons and flywheels
NEXT STEPS
  • Study the relationship between torque and angular acceleration in detail
  • Learn about the moment of inertia for different shapes and how it affects rotational motion
  • Explore the dynamics of pistons and flywheels in mechanical systems
  • Investigate the application of linear equations in rotational dynamics
USEFUL FOR

Mechanical engineers, physics students, and anyone interested in the dynamics of rotational motion and the interplay between linear and angular forces.

a.mlw.walker
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So I have a piston connected to a flywheel. If i push the piston with a force F, how does the equation of motion look? I'm not confident about putting inertias into the same equation as accelerations?

F = ma

F = I(theta'')

The force is changing with time.

EDIT:

So i have just realized that T = Ia, a is angular acceleration.

So if i find resultant force of piston acting along line of tangential velocity on the flywheel, then moultiply it by r of the flywheel,

Fr = Ia, then rearrange for a and i have angular acceleration of flywheel?
 
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Hi a.mlw.walker! :smile:

(have a tau: τ and a theta: θ and an omega: ω and an alpha: α :wink:)
a.mlw.walker said:
So i have just realized that T = Ia, a is angular acceleration.

So if i find resultant force of piston acting along line of tangential velocity on the flywheel, then moultiply it by r of the flywheel,

Fr = Ia, then rearrange for a and i have angular acceleration of flywheel?

That's right …

the standard linear equations apply, with τ I θ ω and α instead of F m s v and a. :wink:
 

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