Solving Force Around a Curve: Tips for Physics Homework

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Homework Help Overview

The original poster is working on a physics homework problem involving forces acting on a driver in a car moving around a curve at different speeds. The problem requires understanding the relationship between speed, force, and mass in the context of circular motion.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of centripetal force equations and the relationship between speed and force without needing mass or radius. There are questions about the mathematical steps involved and how to represent formulas clearly.

Discussion Status

Some participants have provided insights into how to manipulate the equations to find the required force at a new speed. There is an ongoing exploration of the mathematical concepts involved, with participants seeking clarification on specific steps and notation.

Contextual Notes

The original poster expresses concern about their understanding of the problem and the mathematical aspects, indicating a need for further clarification on the concepts and formulas used.

finlejb
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I have this problem as a part of my online phyics homework... it's the first question and I can't figure it out so it doesn't bode well for the rest of the assignment, so I might have to be back a lot before it's due Friday. Any hints on how I should go about solving it?

A curve in a road forms part of a horizontal circle. As a car goes around it at constant speed, 14.7 m/s, the total force on the driver has magnitude 125 N. What is the total vector force on the driver if the speed is 18.9 m/s instead?

I've got that F=ma=m(v^2/r), but I don't have mass or radius, and I don't see any ways of rewriting that formula. I thought about a=change in velocity/change in time, but I don't have time so that doesn't help much either.

By the way, are there any ways to write formulas and such to make them easier to read than how I've been doing it?

Thanks for any help.
 
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Well, you don't have mass or radius. But, it turns out that you don't need to know them either!
[tex]125 = \frac{m(14.7)^2}{r}[/tex]
and you get [tex]m/r = 125/{14.7^2}[/tex]
So, for a new speed, your fictous force turns out to be [tex]F = (125/{14.7^2}) 18.9^2[/tex]
 
I don't quite understand that. I think my problem, though, is in the actual math part, not the concepts...

I've got that F=mass*centripetal acceleration, and you rearranged that to get m/r = F/v^2, but I don't really understand that last step. And how do you type the formulas in the different font?

Thanks for the help though.
 
The last step way simply [tex]F = (m/r) v^2[/tex], I just got m/r from the first equation, and plugged it into the second one. To put it another way,

[tex]F_1 = (m/r) v_1^2[/tex]
[tex]F_2 = (m/r) v_2^2[/tex]

where [tex]F_1 = 125[/tex], [tex]v_1=14.7[/tex] and [tex]v_2=18.9[/tex].
Now, if you divide each equation, [tex]m/r[/tex]s will cancel and you get

[tex]\frac{F_1}{F_2} = \frac{v_1^2}{v_2^2}[/tex]

Made sense?

And, as for the different font thing, it's actually not a different font, but thr output picture of a special language called latex, which is mainly used for writing down mathematical expressions in computers. You can get info that stuff in this topic.
 

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