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I have two second order differential equation which needs to be solved.

x1''(t) = 8 x2(t)

x2''(t) = 2 x1(t)

I have the initial conditions, x1(0) = 0, x2(0) = 1, and terminal conditions x1(pi/4) = 1, x2(pi/4) = 0.

Can anyone help me solve these equations?? What I did was to write the equations in terms of x1 and x2 respectively, but that gives me a fourth order differential

x1''''(t) = 16 x1(t)

x2''''(t) = 16 x2(t)

and I do not know how to solve for these. Can any one help please??

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# Solving fourth order differential equation ( )

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