Solving g(t): Seeking Help with Chain Rule

[spherenine]

Homework Statement

g(t) = 4ln(5ln(4t))

Homework Equations

What is the derivative of g(t)?

The Attempt at a Solution

I have tried to use the chain rule in many different ways, and still can't come up with the correct answer. Anybody care to walk me through this? Is the derivative of ln(4t) still 1/t?

 

[Dick]

(ln(4t))'=(1/(4t))*4=1/t. Yes. It's still 1/t. For your problem g'=4*(1/(5*ln(4t)) times the derivative of 5*ln(4t). What do you make it?

 

[spherenine]

4*(1/(5*ln(4t)) = 4/(5*ln(4t))
Deriv 5*ln(4t) = 5/t

5/t * 4/(5*ln(4t)) = 20/(5t*ln(4t)) = 4/(t*ln(4t)) =

4*(ln(4t))^-1*t^-1?

 

[Dick]

I agree with that.

 

[spherenine]

So does the answer key. Thanks for your help.