Solving Gaussian Problem: Cylindrical Shells w/ Radii R1 & R2

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SUMMARY

The discussion focuses on calculating the electric field (E-field) for a system of two cylindrical shells with radii R1 = 5.0 cm and R2 = 9.0 cm, carrying charges Q1 = +4.2 µC and Q2 = -2.4 µC, respectively. For points inside the inner shell (r = 1.5 cm), the E-field is zero. At r = 5.5 cm, the user incorrectly calculated the E-field as 12.4e6 N/C using the formula E = Q / (4π * ε * r²). For points outside the outer shell (r = 11.5 cm), the user suggested summing the charges to find the E-field but struggled with the calculations.

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Homework Statement



A thin cylindrical shell of radius R1 = 5.0 cm is surrounded by a second cylindrical shell of radius R2 = 9.0 cm, as in the figure. Both cylinders are 5.8 m long and the inner one carries a total charge of Q1 = +4.2 µC and the outer one carries a total charge of Q2 = -2.4 µC. (Assume the positive direction is away from the axis.)

a) r = 1.5 cm
N/C

(b) r = 5.5 cm
N/C

(c) r = 11.5 cm
N/C


Homework Equations



E *Da = Qenclosed/Epsilon

point charge = 1/4pi epsilon * Q/r^2


The Attempt at a Solution



a) radius is smaller than the radius of the first shell, so it's EF = 0
b) I've tried using E = Q / 4pi *epsilon *r^2, but i keep getting the wrong answer = 12.4e6 N/C
c) I think I should add the charges together (-2.4 + 4.2 = 2uC) and use the above equation, but I am at a loss.

I keep trying to find the answers to these last 2, but can't seem to get it right.
 
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do you need to find the E-field at the given r's, at the midplane of the cylinders?
 
"For points far from the ends of the cylinders, determine the electric field at the following radial distances from the central axis."

yes sorry forgot to include that!
 

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