Solving Hamiltonian H=αL⋅S for L⋅S |(ls)jjz>

  • Thread starter Thread starter atomicpedals
  • Start date Start date
  • Tags Tags
    Interaction
Click For Summary
SUMMARY

The discussion focuses on solving the Hamiltonian H=αL⋅S, where L represents angular momentum with quantum number l and S denotes spin with quantum number s. The user attempts to express L⋅S |(ls)jj_{z}> using the formula L⋅S |(ls)jj_{z}> = (ħ²/2)[j(j+1) - l(l+1) - s(s+1)] |(ls)jj_{z}>. The conversation highlights the importance of correctly interpreting the ket notation and clarifies that the alpha term is merely a multiplicative constant affecting energy calculations.

PREREQUISITES
  • Understanding of quantum mechanics, specifically angular momentum and spin.
  • Familiarity with the Hamiltonian operator and its applications in quantum systems.
  • Knowledge of quantum state notation, particularly the ket notation.
  • Basic grasp of the time-independent Schrödinger equation (TISE) for energy spectrum calculations.
NEXT STEPS
  • Study the derivation of angular momentum coupling in quantum mechanics.
  • Explore the implications of the Hamiltonian in quantum systems and its role in energy calculations.
  • Learn about the time-independent Schrödinger equation (TISE) and its applications in determining energy spectra.
  • Investigate the effects of multiplicative constants in quantum mechanics and their influence on physical predictions.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those studying angular momentum and spin interactions, as well as anyone interested in solving Hamiltonian problems in quantum systems.

atomicpedals
Messages
202
Reaction score
7

Homework Statement



Consider the Hamiltonian
H=\alpha L \cdot S
Where L denotes an angular momentum with quantum number l and S a spin with quantum number s.

Work out
L \cdot S |(ls)jj_{z}>
direction. Hint: expand (L+S)2 and go from there.

2. The attempt at a solution

I'm highly tempted to start with
L \cdot S |(ls)jj_{z}> = \frac{\hbar^{2}}{2}[j(j+1)-l(l+1)-3/4]|(ls)jj_{z}>
except I'm not sure that really buys me much. If I'm on the right track, how do I then handle the ket?
 
Physics news on Phys.org
Ok, so my first mistake was probably in my first crack at the solution; so I should probably have started with
L \cdot S |(ls)jj_{z}> = \frac{\hbar^{2}}{2}[j(j+1)-l(l+1)-s(s+1)]|(ls)jj_{z}>
However, my initial self doubts still stand though.
 
That's fine so far. Why are you doubting it's right?

(If you want to derive it, use the hint.)
 
I'm doubting it almost out of habit, lately I've started down the wrong path more often than not.

So, given that I've actually got this one going correctly, what do I do with the information in the ket?

And as a more in-depth question; what does the alpha term do to things when I want to calculate the energy (full disclosure: the follow up question actually is to calculate the energy spectrum, where I would tend to want to start from the TISE)?
 
Last edited:
atomicpedals said:
I'm doubting it almost out of habit, lately I've started down the wrong path more often than not.

So, given that I've actually got this one going correctly, what do I do with the information in the ket?
I'm not sure what you mean by this.

And as a more in-depth question; what does the alpha term do to things when I want to calculate the energy (full disclosure: the follow up question actually is to calculate the energy spectrum, where I would tend to want to start from the TISE)?
It's just a multiplicative constant.
 

Similar threads

Replies
12
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
17
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K