Solving Homework Problems: Understanding Ax and Ay Equations | Get Help Now

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Homework Help Overview

The discussion revolves around understanding the equations for the components of a vector, specifically Ax and Ay, in the context of a physics problem involving vector B represented in three-dimensional space.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of angles between vector B and the coordinate axes, questioning the source of certain numerical values and the correctness of the calculations. There are attempts to derive angles using trigonometric relationships, and some participants express confusion regarding the conversion between radians and degrees.

Discussion Status

The discussion is active with participants raising questions about the accuracy of calculations and the methodology used. There is no clear consensus, as some participants challenge the correctness of the presented values and calculations, while others provide their interpretations of the angles involved.

Contextual Notes

There appears to be confusion regarding the conversion of angles from radians to degrees, which is a point of contention among participants. Additionally, the original poster's attempt at a solution indicates a lack of clarity on how to proceed with the problem.

jaytm2291
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1. Homework Statement
http://gyazo.com/f4c02f2a57b24a39dfee575837e0a807.png


2. Homework Equations
Ax = A cos (?)
Ay = A sin(?)


3. The Attempt at a Solution
I tried putting the magnitude of x cos (?) but honestly have no idea what to do. Thanks
 
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Angle between B and x-axis: arccos(6/sqrt(61))
Angle between B and y-axis: arccos(4/sqrt(61))
Angle between B and z-axis: arccos(3/sqrt(61))
 
Where did you get those numberts?
 
jaytm2291 said:
Where did you get those numberts?

B = 6i + 4j + 3z

Bx = B * cos(angle between x-axis and vector B) ->>cos(angle) = Bx / B ->> angle = arccos(Bx/B)

By = B * cos(angle between y-axis and vector B) ->>cos(angle) = By / B ->> angle = arccos(By/B)

Bz = B * cos(angle between z-axis and vector B) ->>cos(angle) = Bz / B ->> angle = arccos(Bz/B)

B = sqrt(6^2 + 4^2 + 3^2) = sqrt(61)

angle between x-axis and B = arccos(6/sqrt(61))
angle between y-axis and B = arccos(4/sqrt(61))
angle between z-axis and B = arccos(3/sqrt(61))
 
This is wrong. ?
 
jaytm2291 said:
This is wrong. ?

You didnt convert radians to degrees did you, no you didn't

You done didn't, did ya..

x-axis and B = 39.8055 degrees
y-axis and B = 59.1930 degrees
z-axis and B = 67.4114 degrees
 
=) Thank you.
 

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