Solving Homework Statement: Proving a/b=c/d=e/f to ace/bdf

  • Thread starter Thread starter Miike012
  • Start date Start date
Click For Summary

Homework Help Overview

The problem involves proving the equality of two expressions given the relationship a/b = c/d = e/f. The specific expressions to be proven are (a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3) and ace/bdf.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss how to transition from the ratio a/b = c/d = e/f to the given expressions, questioning the relevance of this transition to the proof.
  • There is a consideration of whether the expressions can be simplified or manipulated to demonstrate the equality, with some participants suggesting that the equality holds under certain conditions.
  • Questions arise about the assumptions made in the problem and how they affect the proof process.

Discussion Status

Participants are exploring various interpretations of the problem and discussing the implications of the given assumptions. Some guidance has been offered regarding the structure of a proof, but no consensus has been reached on the specific steps to take.

Contextual Notes

There is an emphasis on understanding the assumptions inherent in the problem, particularly the relationship a/b = c/d = e/f, and how these assumptions influence the proof. Participants express uncertainty about the relevance of the initial expressions provided.

Miike012
Messages
1,009
Reaction score
0

Homework Statement



if a/b = c/d = e/f

then show that...

(a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3) = ace/bdf

Homework Equations




1.I understand how to prove it but I don't understand algebraically how they got from
a/b = c/d = e/f to... (a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3)
( or is this irrelevant and what I should focus on is the proving the theorem?)

2. second I don't understnad how (a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3) = ace/bdf?
the numerator does not simplify into the denominator UNLESS...
because a/b = c/d = e/f

(a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3) could also equal (k^4 + 2k^3 - 3k^4)/(k^4 + 2k^3 - 3k^4) = 1

and ace/bdf could equal k^3/k^3 = 1

therefore 1=1 is true?
 
Physics news on Phys.org
Hi Miike012! :smile:

Start again …

"if a/b = c/d = e/f = p … "
 
then
a=bp, c= dp, and e=fp


I understand that part... is there something that you are hinting at?
 
Miike012 said:
1.I understand how to prove it but I don't understand algebraically how they got from
a/b = c/d = e/f to... (a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3)
( or is this irrelevant and what I should focus on is the proving the theorem?)
It's irrelevant. The expression is a given. You don't care where it comes from.
2. second I don't understnad how (a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3) = ace/bdf?
the numerator does not simplify into the denominator UNLESS...
because a/b = c/d = e/f
The point of the problem is to show that if you assume a/b = c/d = e/f, then (a3b+2c2e-3ae2f)/(b4+2d2f-3bf3) = ace/bdf. All proofs are like this. You're given a set of assumptions, and you want to show that it then follows that some statement is true.
(a^3b + 2c^2e - 3ae^2f) / (b^4 + 2d^2f - 3bf^3) could also equal (k^4 + 2k^3 - 3k^4)/(k^4 + 2k^3 - 3k^4) = 1

and ace/bdf could equal k^3/k^3 = 1

therefore 1=1 is true?
It's certainly true if a, b, c, d, e, and f all equaled each other (and aren't equal to 0), the equality would hold, but that fact doesn't really help in your proof because you're using an assumption that wasn't a given in the problem. All you can assume is a/b = c/d = e/f.
 
wow, thank you ... that makes a lot more sense now.
 
A good way to write a proof like this is to start with one side of the equation and manipulate it until you end up with the other side:

[tex]\begin{align*}<br /> \frac{a^3b + 2c^2e - 3ae^2f}{b^4 + 2d^2f - 3bf^3} & = \cdots \\<br /> & = \cdots \\<br /> & \vdots \\<br /> & = \frac{abc}{def}<br /> \end{align*}[/tex]
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
18
Views
2K
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K