Solving Horizontal Tension: Step-by-Step Guide

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Homework Help Overview

The discussion revolves around understanding the equilibrium of forces and torques in a physics problem involving tension, angles, and gravitational forces. The original poster seeks clarification on a specific equation related to horizontal tension and its components.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between torque and the forces acting on a beam, questioning the meaning of specific terms in the context of the problem. There is a focus on understanding the components of the equation presented by the original poster.

Discussion Status

Some participants have offered insights into the definitions and relationships of torque and distance in the context of the problem. There is ongoing exploration of the concepts involved, with no explicit consensus reached yet.

Contextual Notes

Participants are discussing the implications of angles and distances in the setup of the problem, particularly the importance of the perpendicular distance from the wall and the use of trigonometric functions. There is an indication of confusion regarding the specific terms used in the equation.

fldk31
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Hi guys, I came across this question and I was wondering if someone could explain how we get:
TLsinO - mg(1/2LcosO) = 0
Your help would be much appreciated.

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Do you know how to calculate a torque?
 
t=fd and t-wa ?
 
What does d represent there?
 
distance...
 
Not just any distance. It's specifixally the perpendicular distance from the wall. Since the beam is at an angle, you need the trig equations to find the perpendicular distance.
 
If you understand this, what's the problem to explain it in a couple sentences instead of playing games? If you don't want to explain, it's totally fine.
I am so confused what these two parts mean:
1) TLsinO
2) mg(1/2LcosO)
 
fldk31 said:
If you understand this, what's the problem to explain it in a couple sentences instead of playing games? If you don't want to explain, it's totally fine.
I am so confused what these two parts mean:
1) TLsinO
2) mg(1/2LcosO)
If you are familiar with torque then you should know this: if a force F acts through a point P, the torque the force has about a point Q is F x distance PQ x sin(angle between PQ and the direction of the force).
Can you relate that to the diagram and see how the expressions you quote correspond to the torque exerted by T about the hinge, and the torque the weight of the arm exerts about the hinge?
 

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