Solving Hybridisation: 2pz, 2px, sp3, 2py Bonds

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SUMMARY

The discussion focuses on the types of bonds formed by specific pairs of atomic orbitals: 2pz, 2py, 2px, and sp3. The conclusions are as follows: 2pz and 2pz form a σ bond due to end-on-end overlap; 2py and 2px form a π bond due to side-by-side overlap; sp3 and 2pz do not form a bond because sp3 hybridization does not interact with a p orbital; and 2py and 2py form a σ bond through end-on-end overlap. The analysis assumes that the bonds lie along the z-axis.

PREREQUISITES
  • Understanding of atomic orbitals (2pz, 2py, 2px, sp3)
  • Knowledge of bond types (σ and π bonds)
  • Familiarity with hybridization concepts
  • Ability to visualize orbital overlap
NEXT STEPS
  • Study the principles of orbital hybridization in detail
  • Learn about molecular orbital theory and its applications
  • Explore visual tools for representing atomic orbitals
  • Investigate the role of d orbitals in hybridization (e.g., sp3d)
USEFUL FOR

Chemistry students, educators, and professionals interested in molecular bonding and orbital interactions will benefit from this discussion.

pavadrin
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The problem is as follows:

Decide if the following pairs of orbitals overlap to form a σ bond, π bond, or no bond at
all. Explain your reasoning in each case, including a sketch of the orbitals. Assume the
bond lies along the z-axis.

(a) 2pz and 2pz
(b) 2py and 2px
(c) sp3 and 2pz
(d) 2py and 2py

And here are what I think the solutions are:

(a) 2pz and 2pz will form a σ bond as they are on the same axis and will over lap end-on-end

(b) 2py and 2px will form a π bond as they will over lap side by side

(c) sp3 and 2pz will not form a bond as the next hybridisation is sp3d orbital which contains an electron from a d orbital

(d) 2py and 2py will form a σ bond as they are on the same axis and will over lap end-on-end

If these are wrong could, could you please hint to why, and if I have managed to get something from the textbook (i.e., they are right) could you please help with expanding on the ideas.

Many thanks for your time and replies
pavadrin
 
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pavadrin said:
...(d) 2py and 2py will form a σ bond as they are on the same axis and will over lap end-on-end

Remember the question stated...
Assume the bond lies along the z-axis.

It might help to draw a picture of these two orbitals approaching each other along the z axis and then determine what type of interaction you might expect.
 
thank you, i have now solved the problem as i didn't quite understand what the problem was asking
and i realized i have posted this in wrong section of the forum, sorry
 

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