Solving Impact Acceleration Homework

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SUMMARY

The discussion focuses on calculating the average acceleration of a golf ball that bounces after being dropped from a height of 2.02 meters. The ball rebounds to a height of 0.86 meters and is in contact with the floor for 3.57 milliseconds. To find the average acceleration, it is essential to determine the speed at which the ball hits the floor and the speed at which it leaves the floor after the bounce. The use of gravitational acceleration (9.8 m/s²) is relevant for calculating the initial impact velocity.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Familiarity with concepts of average acceleration
  • Ability to perform calculations involving time and height
NEXT STEPS
  • Calculate the impact velocity using the height of 2.02 m
  • Determine the rebound velocity using the height of 0.86 m
  • Apply the average acceleration formula during the contact time of 3.57 ms
  • Explore the relationship between height, velocity, and acceleration in free fall
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and kinematics, as well as educators looking for examples of real-world applications of acceleration calculations.

Argento7
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Homework Statement



A golf ball released from a height of 2.02 m above a concrete floor, bounces back to a height of 0.86 m. If the ball is in contact with the floor for 3.57 ms( or .00357s), what is the magnitude of the average acceleration a of the ball while it is in contact with the floor?


Homework Equations



Is the .86m bouncing back up irrelevant?


The Attempt at a Solution


I found out that the initial position is 2.02m and the initial position is 0m and I cut the time in half and used 9.8 as my acceleration. I'm just really stuck and have gotten myself caught up in so many different equations my brain can not handle it anymore. Any help would work please.
 
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Argento7 said:

Homework Statement



A golf ball released from a height of 2.02 m above a concrete floor, bounces back to a height of 0.86 m. If the ball is in contact with the floor for 3.57 ms( or .00357s), what is the magnitude of the average acceleration a of the ball while it is in contact with the floor?

Homework Equations



Is the .86m bouncing back up irrelevant?

The Attempt at a Solution


I found out that the initial position is 2.02m and the initial position is 0m and I cut the time in half and used 9.8 as my acceleration. I'm just really stuck and have gotten myself caught up in so many different equations my brain can not handle it anymore. Any help would work please.

You need how far it bounces back to determine the speed it left the floor on the rebound, just as you need the height to determine the speed it hit the floor.
 

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