Solving Impedance Diagrams: Finding i(t) with XL = ωL

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Homework Help Overview

The discussion revolves around solving impedance diagrams in the context of electrical circuits, specifically focusing on the calculation of current i(t) given the inductive reactance XL = ωL.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of inductive reactance and the phase angle, with one participant questioning the method of incorporating the phase angle into the function for i(t). Others suggest showing work to identify potential errors in the calculations.

Discussion Status

The discussion is ongoing, with participants providing guidance on converting inductance to impedance and applying Ohm's law. There is an exploration of different interpretations regarding the calculations and the relationships between voltage, impedance, and current.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information shared and the depth of solutions provided.

k31453
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Homework Statement



Homework Equations


impedence diagram, XL = ωL

The Attempt at a Solution



Ok i got XL = 47 ohm
Then my phase angle is 88.8 degree.

Then to find i(t) i have to add that angle to the function right?
 
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k31453 said:
Ok i got XL = 47 ohm
Then my phase angle is 88.8 degree.

That's not quite right.

If you show your work maybe we can help find where things went wrong.
 
Convert the inductance to an impedance and add it to the resistance. You now have an equivalent circuit with the voltage drop across the impedance given. Use Ohm's law to find the current.

Remember ω = 2*pi*f
 

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