- #1

Jared944

- 10

- 0

Ok, so this problem is kind of complicated, so ask me if you need clarification. This problem deals with Impulse and Momentum.

There are two balls hanging vertically from a horizontal plane. Ball A is pulled back and is set up to strike ball B.

Given for ball A -

mass = 1.5 kg.

Height = .3 m (measured from a horizontal plane from Ball B)

initial speed = 5.00 m/s (as it leaves your hand)

Given for Ball B -

mass = 4.60 kg

speed = 0 m/s (implied)

Question a) is -

Using the principle of conservation of mechanical energy, find the speed of Ball A just before impact.

Question b) is -

Assuming an elastic collision, find the velocities (magnitude and direction) of both balls just after the collision.

I can't quite set up part A, I know I have to integrate a kinematics equation and the principle of conservation of mechanical energy, but I can't quite get it right.

Thanks!

There are two balls hanging vertically from a horizontal plane. Ball A is pulled back and is set up to strike ball B.

Given for ball A -

mass = 1.5 kg.

Height = .3 m (measured from a horizontal plane from Ball B)

initial speed = 5.00 m/s (as it leaves your hand)

Given for Ball B -

mass = 4.60 kg

speed = 0 m/s (implied)

Question a) is -

Using the principle of conservation of mechanical energy, find the speed of Ball A just before impact.

Question b) is -

Assuming an elastic collision, find the velocities (magnitude and direction) of both balls just after the collision.

I can't quite set up part A, I know I have to integrate a kinematics equation and the principle of conservation of mechanical energy, but I can't quite get it right.

Thanks!