Solving Inequalities: Tips & Tricks for Beginners

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When solving inequalities, the direction of the inequality sign changes only when multiplying or dividing by a negative number. For example, in the inequality 3x ≤ 9, the correct solution is x ≤ 3, not x ≥ 3. It's important to verify solutions by substituting values back into the original inequality to ensure they hold true. Additionally, taking the reciprocal of both sides of an inequality also reverses the inequality sign. Understanding these rules is essential for accurately solving inequalities.
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Hi, I used to do all this type of inequalities but I have not practice this for almost a year and I have totally forgotten and didn't know why did the sign change.

For example: If it's 3x ≤ 9
The answer: x ≥ 3

Is this right? I have actually forgotten in what circumstances we are suppose to change the inequalities. Input and explanation will be much appreciation. Thanks!
 
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It's actually the other way around, i.e., x <= 3.
You can always test your answer. For example if x = 1, then 3x <= 9. But x is not greater than 3. Thus your answer is wrong.

You only change the inequality when the coefficient is negative ( -x > 0 <=> x < 0).
 


Rikardus said:
It's actually the other way around, i.e., x <= 3.
You can always test your answer. For example if x = 1, then 3x <= 9. But x is not greater than 3. Thus your answer is wrong.

You only change the inequality when the coefficient is negative ( -x > 0 <=> x < 0).
More precisely, the direction of the inequality changes when you multiply both sides of the inequality by a negative number. This includes division, as well, since division by a number is the same as multiplying by the reciprocal of that number.

The direction of the inequality changes if you take the reciprocal of each side. For example, 2 < 3, but 1/2 > 1/3.
 


All of these replies got it right. What helped me when I was learning about inequalities, was to treat it like an equal sign. Then the only additional thing to remember when solving them is to change the direction of the inequality any time you multiply or divide the equation by a negative number.

Also, as was pointed out above. you can always check to make sure the answer makes sense by plugging it back in.

good luck!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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