Solving Inequality 4x-12≤6x+20

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gazparkin
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Hello,

I'm working on solving linear equalities (with equations) and can anyone help with the below question. I know the answer is -16, but I can't figure out the steps that gets it to this.

4x-12≤6x+20

Once I've evened out the x's on both sides and got this to 2x, I'm then left with -12 and +20, which leaves +8, divided by the remaining 2x, which leaves 4. This isn't correct though, so could anyone help me with the different stages on this.

Thank you!
 
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Hello gazparkin.

gazparkin said:
Once I've evened out the x's on both sides and got this to 2x, I'm then left with -12 and +20, which leaves +8, divided by the remaining 2x, which leaves 4.
You’re on the right line, but when you move the $20$ from the RHS to the LHS, you should have $-20$, not $+20$.

gazparkin said:
the answer is -16
The answer is not just -16. The answer involves $-16$, the variable $x$, and an inequality sign in between. It’s important to get the inequality sign right, or you won’t get any marks for the question.