Solving Infinite Limit Homework with Binomials: Step-by-Step Guide

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SUMMARY

The limit problem discussed involves evaluating the expression \(\lim_{t \to 3^{+}} \frac {y+1}{(y-2)(y-3)}\). The initial attempt incorrectly simplified the denominator to \(y^{2}-5y+5\) and calculated the limit as \(-4\). However, the correct evaluation reveals that as \(y\) approaches 3 from the right, the denominator approaches zero, resulting in the limit approaching infinity. This highlights the importance of recognizing vertical asymptotes in limit problems.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with binomial expressions
  • Knowledge of vertical asymptotes
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Study the concept of vertical asymptotes in calculus
  • Learn about the behavior of limits approaching infinity
  • Practice solving limits involving binomials
  • Review algebraic manipulation techniques for rational functions
USEFUL FOR

Students studying calculus, particularly those focusing on limits and asymptotic behavior, as well as educators looking for examples of common pitfalls in limit evaluations.

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Homework Statement



[tex]\lim_{t \to 3^{+}} \frac {y+1}{(y-2)(y-3)}[/tex]

Homework Equations





The Attempt at a Solution



I thought that this problem looked pretty straight forward but i am obviously doing something wrong. What I did was:

multiply the binomials:

[tex]\lim_{t \to 3^{+}} \frac {y+1}{y^{2}-5y+5}[/tex]

and then apply the limit:

[tex]\frac {3+1}{3^{2}-15+5} = \frac {4}{-1} = -4[/tex]

but this is WAY off because the answer is suppose to be infinity, so what did I forgot from the lesson?...
 
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Check your multiplication again.
 
ha, yep, ok thanks
 

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