- #1
heythere1010
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Homework Statement
A stone is dropped from a bridge that is 65 m high. A second stone is thrown downwards 2 seconds later. Both the stones are heard hitting the water at the same time. The speed of sound is a constant 343 m/s. What is the initial velocity of the second stone.
Homework Equations
d=vi*t+1/2at^2
The Attempt at a Solution
65=0+1/2(-9.8)(t)^2
I know t-2 is used for the time of the second stone. I don't know which equations to use to make them equal.