1. The problem statement, all variables and given/known data A stone is dropped from a bridge that is 65 m high. A second stone is thrown downwards 2 seconds later. Both the stones are heard hitting the water at the same time. The speed of sound is a constant 343 m/s. What is the initial velocity of the second stone. 2. Relevant equations d=vi*t+1/2at^2 3. The attempt at a solution 65=0+1/2(-9.8)(t)^2 I know t-2 is used for the time of the second stone. I don't know which equations to use to make them equal.