Solving Isosceles Triangle Problem with Calculus

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To determine which vertex angle of an isosceles triangle yields the greatest area using calculus, one must derive an equation for the area based on the triangle's dimensions. The area can be expressed as S = (k² * sin(θ)) / 2, where k represents the lengths of the two equal sides and θ is the angle between them. By treating the area as a function of the angle θ, one can apply optimization techniques to find the angle that maximizes the area. This involves differentiating the area function and solving for critical points. Overall, the approach focuses on maximizing the area through calculus principles.
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There was a question on my math test today and i didnt even understand the problem. I want to see if anyone else knows how to do it. So here it goes:
"Use Calculus to prove which vertex angle an isoseles triange the greatest area"

I think your supposed to find a equation for Area and Perimeter. Then take one of the equations and solve for a variable. Plug it into the next equation and then differentiate, like i would do on optimization problems, but i didnt know how to do it with this problem. Below is the figure given.
 

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calvinnn said:
There was a question on my math test today and i didnt even understand the problem. I want to see if anyone else knows how to do it. So here it goes:
"Use Calculus to prove which vertex angle an isoseles triange the greatest area"

I think your supposed to find a equation for Area and Perimeter. Then take one of the equations and solve for a variable. Plug it into the next equation and then differentiate, like i would do on optimization problems, but i didnt know how to do it with this problem. Below is the figure given.

I'm not sure,there might be more to your problem than what i understood:
S_{triangle} =\frac{k^{2}\sin\theta}{2},where k and k are the 2 sides of the isosceles triangle assuled constant and the angle \theta is the angle between the 2 congruent segments.
This of S as a function of only one variable,the angle \theta and use the principle of extremum to find the angle for which the area is maximum.Then find that maximum inserting the value for maxmum in the initial function.

As i said,maybe the problem is more complicated,but for now,try to solve it this way.

Daniel.
 
k thankssss :smile:
 

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