Solving Kinematics Problem: V_o & Max Height

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The discussion revolves around solving a kinematics problem to find the initial velocity and maximum height of an object. The user calculated the time to maximum height as 1.015 seconds and derived an initial velocity of 9.947 m/s. However, they realized that the timing of the events was misunderstood, leading to discrepancies in their height calculation of 4.70 meters. Clarification revealed that the 1.28 seconds mentioned was after the initial 0.75 seconds, affecting the overall calculations. The conversation also included light-hearted banter about climbing trees and humor.
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Homework Statement
John climbs a tree to get a better view of the speaker at an outdoor graduation ceremony. Unfortunately, he leaves his binoculars behind. Marsha throws them up to John, but her strength is greater than her accuracy. The binoculars pass John's outstretched hand after 0.75s and again 1.28s later. How high is John?
Relevant Equations
v_o + at = v_f
v_o*t - 0.5gt^2 = y
For this problem I tried to find when the binoculars reaches the maximum height. So, (0.75 + 1.28)/2 = 1.015s. Using that information I can solve for the initial velocity. v_o = gt = 9.947 m/s.

Then using the initial velocity I can solve for the height of John using the 2nd kinematics equation.

9.947(0.75) - 0.5(9.8)(0.75^2) = 4.70m

I checked the answer and solution, but it was totally different from my answer. What did I do wrong?
 
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DeltaForce said:
How high is John?
Obviously we need more information to answer this question. What was he smoking before climbing the tree? :wink:
For this problem I tried to find when the binoculars reaches the maximum height. So, (0.75 + 1.28)/2 = 1.015s. Using that information I can solve for the initial velocity. v_o = gt = 9.947 m/s.

Then using the initial velocity I can solve for the height of John using the 2nd kinematics equation.

9.947(0.75) - 0.5(9.8)(0.75^2) = 4.70m

I checked the answer and solution, but it was totally different from my answer. What did I do wrong?
Check the wording of the question. The 1.28s is *after* the 0.75s first cross-over time... :smile:
 
Hahahaha, I was sitting there wringing my brain out figuring out what I did wrong. Now I see. Thank you!
 
Happy to help. I try to avoid climbing trees after, well, you know... o0)
 
i dont get it
 
Hristijan said:
i dont get it
What exactly is it that you don't get?
 
kuruman said:
What exactly is it that you don't get?
Probably my witty humor. Not everybody gets me. :wink:
 
berkeman said:
Probably my witty humor. Not everybody gets me. :wink:
Ask whomever you think doesn't get your humor to climb a tree and get high, not necessarily in that order. Say anything and listen for the telltale giggles. On second thought, forget the tree.
 
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