Solving Kinematics Problems: Distance Traveled Before Applying Brakes

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Homework Help Overview

The discussion revolves around a kinematics problem involving the calculation of distance traveled by a driver before applying brakes after noticing an emergency. The scenario presents a speed of 17 m/s and a reaction time of 0.8 seconds.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use the equation d = vt to calculate distance but questions the validity of their initial answer. They consider alternative equations that involve acceleration and express confusion about the necessity of acceleration in this context.

Discussion Status

Some participants affirm the original poster's reasoning and suggest that their initial approach is valid. There is a recognition of the simplicity of the logic used, and the discussion reflects a supportive environment where participants are encouraged to trust their understanding.

Contextual Notes

The original poster expresses uncertainty about their answer and the relevance of acceleration in the problem, indicating a potential misunderstanding of the problem's requirements.

nblu
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Q: The average alcohol-free driver requires about 0.8 s to apply the brakes
after seeing an emergency. Calculate the distance traveled after seeing the emergency
before applying the brakes.

with the question, the given speed is 17 m/s and t = 0.8.
at first, i used d =vt equation to find the distance, however,
when i read through the question again, i had a feeling that it's not right.
my first answer was d=14m, but it just doesn't look correct.

i was thinking of finding the acceleration then use v[tex]^{2}_{f}[/tex]=v[tex]^{2}_{i}[/tex] +2a[tex]\Delta[/tex]d
to solve for d, OR, use this equation, [tex]\Delta[/tex]d=1/2(v[tex]_{1}[/tex]+v[tex]_{2}[/tex])[tex]\Delta[/tex]t, without
even having to find the acceleration.

one part of my knowledge tells me that i don't need acceleration to do this question
because this is about "before" applying the break.

its confusing me..

any help would be greatly appreciated.

thank you
 
Last edited:
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You "know" what you did is right. Resist the temptation to complicate it. I'm sure you'll get a chance to use that other stuff later.
 
nblu said:
with the question, the given speed is 17 m/s and t = 0.8.
at first, i used d =vt equation to find the distance, however,
when i read through the question again, i had a feeling that it's not right.
my first answer was d=14m, but it just doesn't look correct.


one part of my knowledge tells me that i don't need acceleration to do this question
because this is about "before" applying the break.

If Dick's reply isn't enough, your logic is right to me, simple enough. I don't see how it doesn't "look correct".
 
Dick said:
You "know" what you did is right. Resist the temptation to complicate it. I'm sure you'll get a chance to use that other stuff later.

Siracuse said:
If Dick's reply isn't enough, your logic is right to me, simple enough. I don't see how it doesn't "look correct".

Thank you, I really appreciate it! :)
 

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