Solving Kinematics Problems: Distance Traveled Before Applying Brakes

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SUMMARY

The discussion centers on calculating the distance traveled by an alcohol-free driver before applying brakes after noticing an emergency. Given a speed of 17 m/s and a reaction time of 0.8 seconds, the correct formula to use is d = vt, leading to a distance of 13.6 meters. The initial calculation of 14 meters was close but slightly inaccurate due to rounding. The consensus among participants emphasizes the simplicity of the problem, confirming that acceleration is not necessary for this specific calculation.

PREREQUISITES
  • Understanding of basic kinematics equations
  • Familiarity with the concept of reaction time in driving scenarios
  • Knowledge of distance, speed, and time relationships
  • Ability to perform basic arithmetic calculations
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  • Study the kinematic equation d = vt for various scenarios
  • Explore the implications of reaction time on stopping distances
  • Learn about the effects of acceleration on distance calculations
  • Investigate real-world applications of kinematics in driving safety
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Students studying physics, driving instructors, and anyone interested in understanding the practical applications of kinematics in real-life scenarios.

nblu
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Q: The average alcohol-free driver requires about 0.8 s to apply the brakes
after seeing an emergency. Calculate the distance traveled after seeing the emergency
before applying the brakes.

with the question, the given speed is 17 m/s and t = 0.8.
at first, i used d =vt equation to find the distance, however,
when i read through the question again, i had a feeling that it's not right.
my first answer was d=14m, but it just doesn't look correct.

i was thinking of finding the acceleration then use v^{2}_{f}=v^{2}_{i} +2a\Deltad
to solve for d, OR, use this equation, \Deltad=1/2(v_{1}+v_{2})\Deltat, without
even having to find the acceleration.

one part of my knowledge tells me that i don't need acceleration to do this question
because this is about "before" applying the break.

its confusing me..

any help would be greatly appreciated.

thank you
 
Last edited:
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You "know" what you did is right. Resist the temptation to complicate it. I'm sure you'll get a chance to use that other stuff later.
 
nblu said:
with the question, the given speed is 17 m/s and t = 0.8.
at first, i used d =vt equation to find the distance, however,
when i read through the question again, i had a feeling that it's not right.
my first answer was d=14m, but it just doesn't look correct.


one part of my knowledge tells me that i don't need acceleration to do this question
because this is about "before" applying the break.

If Dick's reply isn't enough, your logic is right to me, simple enough. I don't see how it doesn't "look correct".
 
Dick said:
You "know" what you did is right. Resist the temptation to complicate it. I'm sure you'll get a chance to use that other stuff later.

Siracuse said:
If Dick's reply isn't enough, your logic is right to me, simple enough. I don't see how it doesn't "look correct".

Thank you, I really appreciate it! :)
 

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