Solving Kirchoff's Rules - Circuit Analysis Practice

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SUMMARY

The discussion focuses on solving a circuit analysis problem using Kirchoff's Rules, specifically for a circuit involving resistors of 200Ω, 80Ω, 20Ω, and 70Ω. The user initially set up a system of equations to find the currents I1, I2, I3, and I4 but arrived at incorrect values compared to the book's answers. The key error identified was in the application of voltage signs in the equation for I3, where the user failed to recognize that the potentials in series should add, leading to a miscalculation of the potential difference across the resistors.

PREREQUISITES
  • Understanding of Kirchoff's Rules for circuit analysis
  • Familiarity with Ohm's Law (V=IR)
  • Ability to set up and solve systems of linear equations
  • Basic knowledge of electrical circuits and components
NEXT STEPS
  • Review Kirchoff's Voltage Law and its application in circuit analysis
  • Practice solving circuit problems involving multiple resistors and voltage sources
  • Learn how to correctly apply signs in circuit equations to avoid common mistakes
  • Explore advanced circuit analysis techniques such as mesh and nodal analysis
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone looking to improve their skills in circuit analysis and problem-solving using Kirchoff's Rules.

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Homework Statement


In the circuit of Figure P28.28, determine the current in each resistor and the potential difference across the 200-ohm resistor.
FigP28.28.jpg



Homework Equations



Kirchoff's Rules
V=IR

The Attempt at a Solution



The way I did it was like this:
FigP28.28d.jpg

I set up a system of equations-
I1 + I2 + I3 + I4 = 0
- 40 V = I2 (80Ω) - I1 (200Ω)
40 V - 360 V = I3 (20Ω) - I2 (80Ω)
- 360 V - 80 V = I4 (70Ω) - I3 (20Ω)

And I get
I1=1.83 (for 200Ω)
I2=4.07 (for 80Ω)
I3=.30 (for 20Ω)
I4=-6.2 (for 70Ω)
Then I do V=IR to get the potential difference, which I got was 366 volts.

But in the back of the book, it says the answers are:
1.00 A up in 200Ω
4.00 A up in 70 Ω
3.00 A up in 80 Ω
8.00 A down in 20 Ω
200 V

What did I do wrong
 
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40 V - 360 V = I3 (20Ω) - I2 (80Ω)
The signs on the 40V and the 360V should be the same because they are in series - the potentials add.
 
thanks
 

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