There may be simpler ways to solve this, but just go ahead and write the KCL equations and try it that way. Please show your work...Sho Kano said:
berkeman said:There may be simpler ways to solve this, but just go ahead and write the KCL equations and try it that way. Please show your work...
Did you read through the thread that SammyS linked to in post #4?Sho Kano said:
It is usually preferable to not involve more current variables than are needed, to minimise the amount of algebra it generates. Once you label 3 currents, the others are already defined in terms of those 3 so they can be marked on the schematic accordingly.Sho Kano said:
So in the end, I only need 5 equations?NascentOxygen said:
Yes, the currents through R2 are the same and so are the ones for R1 because reversing the polarities would give an identical result.berkeman said:Did you read through the thread that SammyS linked to in post #4?
Symmetry says so. If you can flip or rotate a circuit about one or more axes of symmetry and the result is identical to the original circuit, then the resulting circuit must behave identically to the original and the symmetric pairs of circuit elements must display the same behavior (current, potential difference).Sho Kano said:
Are you trying to say that the current into point A for the non-rotated circuit is the same as the current flowing into point D for the rotated circuit?gneill said:
The magnitude is certainly the same. Change the polarity of the voltage source and the signs of the currents will agree too.Sho Kano said:
Right, charge is conserved. If all the resistors were different, would the current still be the same?gneill said:
Which current? Certainly the current entering (or leaving) node A via the battery is the same as the current leaving (or entering) node D via the battery.Sho Kano said:
I see, so only currents through same resistors will have the same magnitude?gneill said:
Rephrase that as "The currents through the symmetrically paired resistors will be the same" and you would be right. Don't overspecify by saying "only". Some circuits may have resistors of different values that happen to have the same magnitude of current.Sho Kano said:
The currents through the symmetrically paired resistors will be the same.gneill said:
Will there still be the same symmetry?Sho Kano said:
In the un-rotated figure: top left resistor is R1 top right is R2. Bottom left is R3, bottom right is R4. The bridge resistor is R5.SammyS said:
Then the currents will be affected. No more assumptions about one current being the same as another.Sho Kano said:
Kirchoff's method is a set of rules used to analyze complex electrical circuits. It involves applying Kirchoff's current law (KCL) and Kirchoff's voltage law (KVL) to find unknown currents and voltages in a circuit.
To apply Kirchoff's method, you first need to label all the components and nodes in the circuit. Then, use KCL to write down equations for each node and KVL to write down equations for each loop. Finally, solve the equations simultaneously to find the unknown currents and voltages.
Kirchoff's method is a systematic approach that can be applied to any kind of circuit, no matter how complex. It also ensures that the conservation of charge and energy are satisfied, making it a reliable method for circuit analysis.
Kirchoff's method assumes ideal circuit elements and does not take into account factors like resistance, capacitance, and inductance. It also does not consider the effects of non-linear components, making it less accurate for certain types of circuits.
Yes, Kirchoff's method can be used for both DC and AC circuits. However, for AC circuits, the equations become more complex due to the presence of reactance (X) in addition to resistance (R).