Solving Lagrange Charpit Homework Equation

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The discussion focuses on solving the equation 4u∂u/∂x = (∂u/∂x)² using Charpit's equations. The initial conditions are parameterized from the line x + 2y = 2, leading to expressions for x and y in terms of a parameter s. The Charpit equations derived include dx/dt = 4u, dy/dt = -1, and others related to the variables p and q. The next step involves determining how to express du/dt, which should be set to -q². Participants are seeking guidance on progressing from this point in the solution process.
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Homework Statement



Use Charpits equations to solve 4u\frac{\partial u}{\partial x} = (\frac{\partial u}{\partial x})^2

where u=1 on the line x+2y=2

Homework Equations





The Attempt at a Solution


from the charpit equations i get
\frac{dx}{dt} = 4u
\frac{dy}{dt} = -1
\frac{du}{dt} = 4pu-q
\frac{dp}{dt} = -4p^2
\frac{dq}{dt} = -4pq

next i have to parameterise the inital conditions
the line x+2y=2
x=s
y=\frac{2-s}{2}

whats the next step?
 
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du/dt should be -q^2
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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