Solving Lagrange Charpit Homework Equation

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SUMMARY

The forum discussion focuses on solving the Lagrange Charpit equation, specifically the equation 4u∂u/∂x = (∂u/∂x)². The user derives the Charpit equations: dx/dt = 4u, dy/dt = -1, du/dt = 4pu - q, dp/dt = -4p², and dq/dt = -4pq. They also parameterize the initial conditions along the line x + 2y = 2, using x = s and y = (2 - s)/2. The user seeks guidance on the next steps, particularly regarding the derivative du/dt.

PREREQUISITES
  • Understanding of Charpit's equations
  • Familiarity with partial differential equations (PDEs)
  • Knowledge of parameterization techniques
  • Basic calculus, particularly derivatives and their applications
NEXT STEPS
  • Explore the method of characteristics for solving PDEs
  • Study the implications of initial conditions on solution behavior
  • Investigate the relationship between parameterization and solution curves
  • Learn about the stability of solutions in Charpit's method
USEFUL FOR

Mathematics students, particularly those studying differential equations, and educators looking to enhance their understanding of Charpit's method in solving PDEs.

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Homework Statement



Use Charpits equations to solve 4u[itex]\frac{\partial u}{\partial x}[/itex] = [itex](\frac{\partial u}{\partial x})^2[/itex]

where u=1 on the line x+2y=2

Homework Equations





The Attempt at a Solution


from the charpit equations i get
[itex]\frac{dx}{dt}[/itex] = 4u
[itex]\frac{dy}{dt}[/itex] = -1
[itex]\frac{du}{dt}[/itex] = 4pu-q
[itex]\frac{dp}{dt} = -4p^2[/itex]
[itex]\frac{dq}{dt} = -4pq[/itex]

next i have to parameterise the inital conditions
the line x+2y=2
x=s
y=[itex]\frac{2-s}{2}[/itex]

whats the next step?
 
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du/dt should be -q^2
 

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