Solving Laplacian Operators and DEs

  • Thread starter Thread starter Hertz
  • Start date Start date
  • Tags Tags
    Curious
Click For Summary
The discussion focuses on solving the Laplacian operator equation, specifically the form ∇²U(𝑟) = C(𝑟)U(𝑟), and its one-dimensional counterpart d²U/dx² = C(x)U(x). The user is seeking methods to solve for U(x) in terms of C(x) and is uncertain about the existence of such solutions. Suggestions include starting with the case where C is constant, which leads to the Helmholtz equation, and considering boundary conditions to facilitate integration. The conversation also touches on the potential forms of the Laplacian operator in spherical or polar coordinates, indicating a willingness to explore further.
Hertz
Messages
180
Reaction score
8
Hi, lately I've been messing around a lot with the Laplacian operator and DE's including the Laplacian operator. Most recently, the equation below is the one I have been messing around with and trying to understand better.

\nabla^2 U(\vec{r})=C(\vec{r})U(\vec{r})

This is pretty general though.. WAYY too general for me to tackle. So I've been starting with the 1D case, which I also can't seem to solve.

\frac{d^2}{dx^2}U(x)=C(x)U(x)

My goal is to try to solve for U(x) in terms of C(x). Any ideas? Is there any way to know if such a solution exists? What about to the general equation above?

Thanks :)
 
Last edited:
Physics news on Phys.org
Do you know the form of the Laplacian operator in spherical or polar coordinates
 
No I don't but it wouldn't be too much of a hassle to figure it out. How could that help though?
 
A couple of thoughts for progressing.

1) Try the case where C is constant. This actually gives you a Helmholtz equation.

2) For the more general case, it helps to assume that U or U dot n =0 at the boundary and C has a certain sign.
Then multiply by U and integrate over the domain, this will involve an integration by parts.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
5K
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
5
Views
2K