Solving ln|(1-z)/(z+3)| = (ln|v| + c)2

[franky2727]

iv egot 1/2ln|(1-z)/(z+3)|=Ln|v|+c
does this go to ln |(1-z)/(z+3)|^1/2=Ln|v|+c

which goes to ln|(1-z)/(z+3)|=(ln|v| +c)²

 

[nicksauce]

No it's not right. a*log(x) = log(x^a), not (log(x))^a.