The discussion revolves around solving logarithmic equations using given logarithmic values for specific numbers. The participants are exploring how to apply logarithmic properties to find values for loga(130), loga(1.3), and loga(1000).
Some participants have provided guidance on using logarithmic rules, such as the product rule. There is a recognition of the need to express numbers in terms of known logarithmic values, and some participants have indicated they are beginning to understand the process, while others still express confusion.
Participants mention missing information from a previous class and express uncertainty about the application of logarithmic rules. There is a focus on understanding how to manipulate logarithmic expressions without providing complete solutions.
Everstar said:well i think you getting at something like this
so if i have logam+logan
i get loga(m)(n)
Everstar said:well I'm not sure if I am correct but i multiplied the two numbers 2.4197*2.6955 = 6.522
Everstar said:well then i just get log_a(10)(13) which is 130 but i don't understand what i am supposed to do with that? I am sorry I am just confused
Everstar said:oh my goodness lol i add them =)
Yes, log(1000)= log(10*10*10)= log(10)+ log(10)+ log(10). Of course, that's the same as 3*log(10). That's another "rule of logarithms": log(xy)= y log(x).Everstar said:i figured it out thank you for the help =) i add the first one then divide (subtract the second one, then add add add on the third one. thanks =)