Solving Math Induction Homework: Proving LHS=RHS

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SUMMARY

The discussion focuses on proving the equality of the left-hand side (LHS) and right-hand side (RHS) of a mathematical expression involving factorials. The specific equation under scrutiny is 1 - [1 / (x+2)!] = [1 / (x+1)!] + [(x+1) / (x+2)!]. Participants suggest simplifying the expression by obtaining a common denominator and rewriting (x+2)! as (x+2)(x+1)!. The key insight is to factor out (x+1)! from the numerator of the second term for simplification.

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  • Ability to manipulate algebraic fractions
  • Basic knowledge of common denominators in fractions
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Students studying mathematics, particularly those tackling algebraic proofs and mathematical induction, as well as educators looking for effective teaching strategies in these areas.

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Homework Statement



trying to prove left-hand side = right-hand side

this is where I'm stuck:

<br /> 1 - [1 / (x+1)!] + [(x+1) / (x+2)!] = 1 - [1 / (x+2)!]<br />

Homework Equations





The Attempt at a Solution



i tried this but can't get anywhere

get a common demoninator:
1 - [(x+2)! + (x+1)*(x+1)! / (x+1)!*(x+2)!]

anyone seeing what I'm not seeing?
 
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get a common demoninator:
1 - [(x+2)! + (x+1)*(x+1)! / (x+1)!*(x+2)!]

That should be a minus.

Pull out the (x+1)! from the numerator of the second term and simplify.
 
A useful trick is to write (x+2)! as (x+2)(x+1)!
 

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