Solving Matrix/Error Proof? Get a Hint Here!

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Homework Help Overview

The discussion revolves around a proof related to approximation errors in the context of matrix operations. Participants are exploring the relationship between sequences defined by the equation x = Tx + b, where T is a matrix and b is a vector.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants suggest taking norms of both sides of the equation and substituting values to explore the behavior of the sequence. There are attempts to establish inequalities involving the norms and the matrix T, with some questioning the steps needed to relate different terms in the sequence.

Discussion Status

Several participants have provided hints and partial approaches to the problem, focusing on the manipulation of norms and inequalities. There is an ongoing exploration of how to connect various terms in the sequence, with some participants seeking clarification on the relationships between them.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the extent of direct solutions provided. There is a noted ambiguity in the relationships being analyzed, particularly regarding the transitions between terms in the sequence.

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Homework Statement



Not too sure what this proof would be under, but am pretty sure it has to do with approximation errors, can anyone give me a hint as to how to even start this?


Homework Equations





The Attempt at a Solution



For the first one, my guess at the solution would be...

1)take the norm of both sides of x = Tx + b
2) then substitute in x^k = Tx^(k-1) + b into the x's
3)since x^k = Tx^(k-1) + b, we get norm( x^k = T(Tx^(k-1) + b) + b), which then we get infinite multiples of T. Hence T^k?

That's really wild guess at the solution, any help would be much appreciated
 

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for the first part you might look at something like
|xk+1 - x| = |(Txk + b) - (Tx + b)| = |T(xk -x)|
and continue till k->0.


for the second, maybe try to establish something like
|xk - x| <= ||T|| |xk-1 - x| <= ||T|| ( |xk-1 - xk| + |xk - x|).

Then solve for |xk - x| in terms of |xk-1 - xk|.

And then try to figure out how to go from
|xk-1 - xk| to |x0 - x1|.
 
qbert said:
for the first part you might look at something like
|xk+1 - x| = |(Txk + b) - (Tx + b)| = |T(xk -x)|
and continue till k->0.for the second, maybe try to establish something like
|xk - x| <= ||T|| |xk-1 - x| <= ||T|| ( |xk-1 - xk| + |xk - x|).

Then solve for |xk - x| in terms of |xk-1 - xk|.

And then try to figure out how to go from
|xk-1 - xk| to |x0 - x1|.
Dear qbert

For the 2nd part of the question. Are we meant to figure out how to go from |xk - xk-1| to |x1 - x0| rather than the given above |xk-1 - xk| to |x0 - x1|

my attempt at the question is as follows

||x(k) - x|| <= ||T|| ||x(k-1) - x(k)|| + ||T|| ||x(k) - x||

||x(k) - x|| - ||T|| ||x(k) - x|| <= ||T|| ||x(k-1) - x(k)||

||x(k) - x|| (1 - ||T||) <= ||T|| ||x(k-1) - x(k)||

solving for ||x(k) - x|| <= (||T||/(1 - ||T||)) ||x(k-1) - x(k)||

hence my query above.

Kind regards,
kcp
 
qbert said:
for the first part you might look at something like
|xk+1 - x| = |(Txk + b) - (Tx + b)| = |T(xk -x)|
and continue till k->0.


for the second, maybe try to establish something like
|xk - x| <= ||T|| |xk-1 - x| <= ||T|| ( |xk-1 - xk| + |xk - x|).

Then solve for |xk - x| in terms of |xk-1 - xk|.

And then try to figure out how to go from
|xk-1 - xk| to |x0 - x1|.


Dear qbert

For the 2nd part of the question. Are we meant to figure out how to go from |xk - xk-1| to |x1 - x0| rather than the given above |xk-1 - xk| to |x0 - x1|

my attempt at the question is as follows

||x(k) - x|| <= ||T|| ||x(k-1) - x(k)|| + ||T|| ||x(k) - x||

||x(k) - x|| - ||T|| ||x(k) - x|| <= ||T|| ||x(k-1) - x(k)||

||x(k) - x|| (1 - ||T||) <= ||T|| ||x(k-1) - x(k)||

solving for ||x(k) - x|| <= (||T||/(1 - ||T||)) ||x(k-1) - x(k)||

hence my query above.

Kind regards,
kcp
 

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