Solving Maximum Acceleration for 4WD Car on Dry Road

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SUMMARY

The maximum forward acceleration of a four-wheel drive car with a mass of 1000 kg on a dry road is calculated using the formula F = μ x Fn, where μ is the coefficient of static friction (0.8) and Fn is the normal force (weight of the car). The calculation yields a force of 7840 N, resulting in an acceleration of 7.84 m/s² when divided by the mass. This method accurately determines the maximum acceleration without wheel spin, confirming the initial assessment as correct.

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  • Understanding of Newton's Second Law of Motion
  • Knowledge of static friction and its coefficient
  • Basic physics concepts related to force and acceleration
  • Familiarity with the formula F = μ x Fn
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  • Research the effects of different surface conditions on vehicle acceleration
  • Learn about the role of weight distribution in vehicle performance
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Automotive engineers, physics students, and anyone interested in vehicle performance optimization on various road surfaces.

jhk_1945
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A car with four-wheel drive has a mass of 1000kg. Its weight is evenly distributed on its four wheels. The coefficient of static friction with the dry road is 0.8. The car starts from rest on a horizontal surface. What is the greatest forward acceleration that the car can ahcieve without spinning its wheels?

I simply said F = mu x Fn
= 0.8x1000x9.8=7840N

and divided that by the mass to get 7840 / 1000 = 7.84 m/s^2

But I feel that this is isn't correctly answering the question. Can anyone please help me out!?

Thanks
 
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I don't see what else u could do. Seems perfect 2 me
 

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